Résoudre chaque Equitation : a) 3 (2x +5) = -7 (3 -2x) b) 4 ( 2- 8x) - 3 (-9x + 1 ) = 0
Mathématiques
manoulet21
Question
Résoudre chaque Equitation :
a) 3 (2x +5) = -7 (3 -2x)
b) 4 ( 2- 8x) - 3 (-9x + 1 ) = 0
a) 3 (2x +5) = -7 (3 -2x)
b) 4 ( 2- 8x) - 3 (-9x + 1 ) = 0
2 Réponse
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1. Réponse aminerbt
a)
3 (2x +5) = -7 (3 -2x)
6x +15 = -21 +14x
6x -14x = -21 -15
-8x = - 36
x = 36 /8
x= 18 /4
x= 9/2
b)
4 ( 2- 8x) - 3 (-9x + 1 ) = 0
8 - 32x + 27x -3 =0
- 5x + 5 =0
-5x = -5
x = 5/5
x=1 -
2. Réponse ouafuaf
a)= 3(2x + 5) = -7(3-2x)
a) 6x + 15 = -21 +14x
a) 6x+15-15 = -21 + 14x -15
a) 6x -14x= -21 -15 + 14x - 14x
a) -8x = -36
a) -8x/-8 = -36/-8
a) x= 4.5