Bonjour, voici ma factorisation: x²-1+(2x5)(x-1)-3x+3+x-1 =x(x+2+1-3)+5+3 x(x+1)+8 Est-ce bon? Merci :)
Mathématiques
Kito638
Question
Bonjour, voici ma factorisation:
x²-1+(2x5)(x-1)-3x+3+x-1
=x(x+2+1-3)+5+3
x(x+1)+8
Est-ce bon? Merci :)
x²-1+(2x5)(x-1)-3x+3+x-1
=x(x+2+1-3)+5+3
x(x+1)+8
Est-ce bon? Merci :)
1 Réponse
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1. Réponse aminerbt
x²-1+(2x+5)(x-1)-3x+3+x-1 = x²-1+(2x+ 5)(x-1)-2x+2
= x²-1+(2x+ 5)(x-1)-2(x-1)
= x²-1+(2x+ 5)(x-1)-2(x-1)(x+1+2x+5-2)
= (x-1)(x+1+2x+5-2)
= (x-1)(3x+4)